A low-rank window matrix
Penguin learning project
The project uses 342 complete Palmer penguin records: 240 training-pool and 102 held-out rows. The selected training rows determine feature scaling and model parameters. Source CSV
This project trains weights with softmax, unlike the homepage lab, which uses nearest species averages. Same penguin measurements; different classification methods. Predictions can differ.
Frames and sparse signals · Encode or reconstruct signals with frames and dictionaries.
The project scales bill and flipper measurements using training-row means and scales; its feature vector has two entries.
Consider this concept alongside the project; its source assumptions may differ. These observations do not prove a theorem.
Input: 12 × 2; Held-out evaluation: 102 · #58 · 40.6 mm, 193 mm. Known answer: Adélie; Prediction: Adélie · [≈0.7383, ≈0.2444, ≈0.01737].
Used in these source sections: 6.3 Taking apart and rebuilding
A rank-r window matrix has r nonzero singular directions.
This example makes the source notation or condition concrete.
Source formula example
illustration · This rank-one example does not characterize arbitrary window matrices.
Symbols
- d by n circular window matrix.
- Matrix rank.
- Numbers of selected left and right singular vectors.
- Window size.
Source formula example
This source example uses its own inputs and assumptions. Editing it does not change the project.
Edit a value or the code, then run the example. This is a finite demonstration, not a proof of the paper’s theorem.
This example’s data flow
Code changed. Reset to restore this example’s data flow.
You choose
input.value= 1
Initial values in code
d=3n=2r=1p=1q=1
Calculated here
Result expression: { H, d, n, p, q, r, singularValue, rankCondition: p === q && q === r && r <= n }
value=input.valueUses:input.valueH=[ [value, value], [value, value], [value, value], ]Uses:valuesingularValue=Math.sqrt(6) * Math.abs(value)Uses:value
Returns
H- array (3 items): [array (2 items): [1, 1], array (2 items): [1, 1], array (2 items): [1, 1]]
d- 3
n- 2
p- 1
q- 1
r- 1
singularValue- ≈2.449
rankCondition- true
Read numbers from input and return the result. JavaScript basics.
Result
Technical statement
For x=[value,value,value] with value>0, H is a nonzero 3 by 2 constant matrix of rank 1, and its only nonzero singular value is √6 times value. The source chooses p=q=r≤n in its singular-vector discussion.
Source: Source expression