Risk on a separate test sample
Penguin learning project
The project uses 342 complete Palmer penguin records: 240 training-pool and 102 held-out rows. The selected training rows determine feature scaling and model parameters. Source CSV
This project trains weights with softmax, unlike the homepage lab, which uses nearest species averages. Same penguin measurements; different classification methods. Predictions can differ.
Classification predicts three species; Ridge predicts body mass in grams using the same observations. These are separate models. Training predictions feed the objective; 102 separate test predictions never update the weights.
Risk and assessment · Distinguish loss on a sample from expected loss.
The fitted rule is evaluated on 102 held-out observations, not used for fitting.
Held-out evaluation
- Input
- 102 · #58: 40.6 mm, 193 mm
- Output
- Known answer: Adélie; Prediction: Adélie · [≈0.7383, ≈0.2444, ≈0.01737]; Held-out mean loss: ≈0.1639 (cross-entropy); Correct: 99/102
Project operation
The project calculation uses these records; the source formula and example follow below. Code edits run locally; project settings travel between pages.
Prediction → Held-out evaluation → Held-out evaluation
Project input
Showing first three entries; the operation receives the complete array. Rounded preview; the operation uses full precision.
input.task· Project settings or constantclassificationinput.predictions· Prediction[Species: Adélie · Probabilities: [≈0.7383, ≈0.2444, ≈0.01737], Species: Adélie · Probabilities: [≈0.533, ≈0.2223, ≈0.2447], Species: Gentoo · Probabilities: [≈0.0001477, ≈0.001447, ≈0.9984]] … (102 entries)input.targets· Observations[0, 0, 2] … (102 entries)input.rows· Observations[Species: Adélie · Mass (g): 3800, Species: Adélie · Mass (g): 4000, Species: Gentoo · Mass (g): 5250] … (102 entries)
Result
Mean loss: ≈0.1639 · Correct: 99 · Total: 102
Used in these source sections: 1.3 The questions ahead
Train a rule on sample s, then average its losses on a separate sample s-tilde.
The toy rule always predicts 0; the separate test labels are [0,1,1].
A separate test sample can estimate performance on new data.
Source formula example
illustration · This finite test mean is not generally equal to population risk. The toy test data are fixed and invented.
Symbols
- A rule learned from the training sample s.
- A separate test sample.
Source formula example
This source example uses its own inputs and assumptions. Editing it does not change the project.
Edit a value or the code, then run the example. This is a finite demonstration, not a proof of the paper’s theorem.
This example’s data flow
Code changed. Reset to restore this example’s data flow.
You choose
input.prediction= 0
Initial values in code
testLabels=[0, 1, 1]
Calculated here
Result expression: {
testLabels,
prediction,
losses,
testRisk: losses.reduce((a, b) => a + b, 0) / losses.length,
}
prediction=input.predictionUses:input.predictionlosses=testLabels.map((label) => (prediction === label ? 0 : 1))Uses:testLabels,prediction
Returns
testLabels- array (3 items): [0, 1, 1]
prediction- 0
losses- array (3 items): [0, 1, 1]
testRisk- ≈0.6667
Read numbers from input and return the result. JavaScript basics.
Result
Technical statement
The source describes independent test examples drawn from the same population as the training data. The code evaluates a supplied rule on a fixed toy test sample; it does not train the rule or simulate sampling.
Source: Test sample risk