Empirical risk
Penguin learning project
The project uses 342 complete Palmer penguin records: 240 training-pool and 102 held-out rows. The selected training rows determine feature scaling and model parameters. Source CSV
This project trains weights with softmax, unlike the homepage lab, which uses nearest species averages. Same penguin measurements; different classification methods. Predictions can differ.
Classification predicts three species; Ridge predicts body mass in grams using the same observations. These are separate models. Training predictions feed the objective; 102 separate test predictions never update the weights.
Objectives · Combine losses and penalties into a criterion for parameters or rules.
Project predictions and known answers produce losses. Classification uses cross-entropy and α/2 times squared non-bias weights; Ridge uses normalized-mass MSE and α times all squared coefficients, including the intercept.
Mean training loss
- Input
- 12 Loss
- Output
- ≈0.228
Project operation
The project calculation uses these records; the source formula and example follow below. Code edits run locally; project settings travel between pages.
Loss → Mean training loss → Objective
Project input
Showing first three entries; the operation receives the complete array. Rounded preview; the operation uses full precision.
input.losses· Loss[≈0.005482, ≈1.012, ≈0.1422] … (12 entries)
Result
≈0.228
Used in these source sections: 1.2 Learning from examples · 1.2.1 Finding better settings · 1.2.3 Does it work on new examples? · More source sections
Compute the loss for every training example, then average those losses.
Training loss is measurable on the available sample.
Source formula example
exact · The result is exact for these finite toy inputs, apart from ordinary computer rounding.
Symbols
- A sample of m examples.
- Loss of prediction rule f on example z.
Source formula example
This source example uses its own inputs and assumptions. Editing it does not change the project.
Edit a value or the code, then run the example. This is a finite demonstration, not a proof of the paper’s theorem.
This example’s data flow
Code changed. Reset to restore this example’s data flow.
You choose
input.first= 1
Calculated here
Result expression: { losses, risk: losses.reduce((a, b) => a + b, 0) / losses.length }
losses=[input.first, 4, 9]Uses:input.first
Returns
losses- array (3 items): [1, 4, 9]
risk- ≈4.667
Read numbers from input and return the result. JavaScript basics.
Result
Technical statement
This computes a sample average of losses, not an expectation over the whole population.
Source: Source expression