Finite Rayleigh quotient and local energy
Penguin learning project
The project uses 342 complete Palmer penguin records: 240 training-pool and 102 held-out rows. The selected training rows determine feature scaling and model parameters. Source CSV
This project trains weights with softmax, unlike the homepage lab, which uses nearest species averages. Same penguin measurements; different classification methods. Predictions can differ.
Quantum models · Describe wavefunctions, particle coordinates and energy relations.
PDE and quantum models are not operations on these penguin measurements.
Consider this concept alongside the project; its source assumptions may differ. These observations do not prove a theorem.
Input: 12 × 2; Held-out evaluation: 102 · #58 · 40.6 mm, 193 mm. Known answer: Adélie; Prediction: Adélie · [≈0.7383, ≈0.2444, ≈0.01737].
Used in these source sections: 8.2 Equations as guides
For a finite real state, weight each local energy by the squared state value divided by the total squared length.
These expressions specify the inverse or quantum model.
Source formula example
illustration · The invented finite inputs illustrate this expression. They do not prove a general identity, bound, or existence claim.
Symbols
- Nonzero square-integrable wavefunction in the operator domain.
- Hamiltonian with fixed nuclei.
- Random configuration distributed with density |ψ|²/‖ψ‖².
- Complex conjugate of ψ.
- Integral of |ψ|².
Source formula example
This source example uses its own inputs and assumptions. Editing it does not change the project.
Edit a value or the code, then run the example. This is a finite demonstration, not a proof of the paper’s theorem.
This example’s data flow
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input.second= 1
Calculated here
Result expression: {
probabilities,
localEnergy,
expectedEnergy: probabilities.reduce((sum, p, i) => sum + p * localEnergy[i], 0),
quotient: psi.reduce((sum, v, i) => sum + v * Hpsi[i], 0) / normSquared,
}
psi=[1, input.second]Uses:input.secondHpsi=[2 * psi[0], 4 * psi[1]]Uses:psinormSquared=psi.reduce((sum, v) => sum + v * v, 0)Uses:psiprobabilities=psi.map((v) => (v * v) / normSquared)Uses:psi,normSquaredlocalEnergy=Hpsi.map((v, i) => v / psi[i])Uses:Hpsi,psi
Returns
probabilities- array (2 items): [0.5, 0.5]
localEnergy- array (2 items): [2, 4]
expectedEnergy- 3
quotient- 3
Read numbers from input and return the result. JavaScript basics.
Result
Technical statement
This is an exactly enumerated finite distribution for a real nonzero state and diagonal H. The source uses a normalized |ψ|² probability density and a continuous Hamiltonian. Local energy requires ψ ≠ 0 at the evaluated point.
Source: Source expression